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Blazing goIITian

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17 Dec 2009 16:55:15 IST

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951

bond order?

None

how do you calculate bond order of Co2,Na2o2? Pls explain!

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newton

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17 Dec 2009 17:01:29 IST

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please!!!!!!!!!!!

newton

Blazing goIITian

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18 Dec 2009 10:38:33 IST

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????????????????

newton

Blazing goIITian

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19 Dec 2009 18:54:27 IST

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!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11

newton

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21 Dec 2009 19:09:33 IST

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k m sridhar

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21 Dec 2009 19:16:40 IST

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The formula for bond order is calculated using the formula (nb-na)/2

nb- total electrons in bonding orbitals

na- total electrons in anti bonding orbitals.

step one.

Draw the molecular orbital configuration for both the molecules.

count the number of electrons in bonding and antibonding orbitals

apply the formula given above.

newton

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21 Dec 2009 19:18:24 IST

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i know that but can u do the two of them here since i am getting it wrong

Vikram Saxena

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21 Dec 2009 23:25:20 IST

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hiiii

!!!!!

dev_22oct

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21 Dec 2009 23:52:33 IST

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bond order of co2 is 2 coz there is double bond b/w c and o ..where as fr Na2O2 its peroxide..u can calculate it frm the formula that people have gvn already...

dev_22oct

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21 Dec 2009 23:52:34 IST

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bond order of co2 is 2 coz there is double bond b/w c and o ..where as fr Na2O2 its peroxide..u can calculate it frm the formula that people have gvn already...

k m sridhar

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22 Dec 2009 00:07:49 IST

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The Molecular orbital configuration of CO₂ is follows

Bonding Orbitals- MO1 ,MO4,MO5,MO7

ANTIBONDING ORBITAL -MO2, 3 ,6,8

NON BONDING ORBITALS- MO 9 ,10,11,12

NO OF ELECTRONS =16

NO OF ELECTRONS IN BODING ORBITALS = 8

nO OF ELECTRONS IN ANTIBONDING ORBITALS= 0

NO OF ELECTRONS IN NON BONDING ORBITALS= 8

BOND ORDER = 8/2 = 4 AS THERE ARE TWO OXYGEN ATOMS THE BOND ORDER OF ONE C=O IS 4/2=2

k m sridhar

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22 Dec 2009 00:20:56 IST

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BOND ORDER BETWEEN ANY PAIR OF BONDS IS NO OF SHARED PAIRS IN X-Y LINKS/NO OF X-Y PAIRS IN THE MOLECULEFOR EXAMPLE IN OZONE THERE ARE 3 BOND PAIRS BETWEEN TWO MOLECULES HENCE BOND ORDER OF O3= 3/2 =1.5

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