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Physical Chemistry
A solution contains 10% of ethanol and 90% water what is the mole percent of ethanol in the solution.
mol. wt of ethanol C2H5OH = 24 + 6+16 = 46 ..
no/- of moles in 10 g = 10/46 = 0.2174
no/- moles of waer in 90 g water = 90/18 = 5
so, mole % = 0.2174*100 / (5 +0.2174) = 4.17% ..
so,mole percent of ethanol is 4.17 %
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mol. wt of ethanol C2H5OH = 24 + 6+16 = 46 ..
no/- of moles in 10 g = 10/46 = 0.2174
no/- moles of waer in 90 g water = 90/18 = 5
so, mole % = 0.2174*100 / (5 +0.2174) = 4.17% ..
so,mole percent of ethanol is 4.17 %