IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry - calculate total no of electrons in 1.6gm of methane

saya

calculate total no of electrons in 1.6gm of methane

jatinroxx

NO of e- = No of electrons present in 1 molecule of CH4 * molecules of CH4

= 10 * .1 NA

= NA

NA is Avogadro's number...

somyekathait

Here's the answer

moles of CH₄=1.6/16 =1/10=0.1

now molecules of CH₄=0.1 X 6.02 X 10²³

Now 1 molecule of methane has 16 electrons

so 0.1 X 6.02 X 10²³has 0.1 X 16 X 6.02 X 10²³electrons

= 1.6 X 6.02 X 10²³

somyekathait

PLESE RATE ME

rohitkuruvila

given mass of methane[CH₄]=1.6 g

no.of moles of methane=(1.6/16) [since no.of moles=given mass/molar mass]

=0.1

since one carbon atom[E.C.=2,4] has 6 electrons,and four hydrogen atoms[E.C.=1] have four electrons,

therefore

no.of electrons in one mole of methane=6+4

=10

total no.of electrons in given mass=10*0.1*6.023*10²³

=6.023*10²³electrons