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Physical Chemistry

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26 Jan 2012 18:40:05 IST

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chemical equil

Chemistry

Licl.3NH₃(s)--->Licl.NH₃(s) + 2NH₃(g)

at eqil K_p=9atm² at 37^o C. A 5 L vessel contain 0.1 mole of Licl.NH₃. How many moles of NH₃ should be added to the flask at this temp to derive the backward rxn for completion.

a]0.2

b]0.59

c]0.69

d]0.79

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Arjun Virmani

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Joined: 1 Jun 2009

Posts: 1294

28 Jan 2012 03:08:18 IST

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K_p= P[NH₃] ² = 9atm²

P[NH₃] = 3 atm

T = 300K

R = 0.082 L atm / K-mol

V = 5L

by PV= nRT

n = PV / RT

n = 3 * 5 / 0.082 * 300 = 5 / 8.2057 = 0.6093

and

0.1 mole of LiCl.NH₃ req. 0.2 mol .NH₃

Total 0.809 mol.!!!

option 4) 0.79 mol!!!

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