For the decomposition of azoisopropane to hexane and nitrogen at 543 K , the following data are obtained

t=0 sec                          P(mm of Hg)=35.0

t(sec)=360                   P(mm of Hg)=54.0

t(sec)=720                   P(mm of Hg)=63.0

Calculate the rate constant.

please reply me.rates assured

k = {2.303/t} log [P_o(y-1) / yP_o - P_t ]

here k = rate constant

P_o = initial pressure

P_t = pressure at that instant

y = no. of products

t = time

substitute the given values u get the answer as

k = 2.175 * 10^-3 s^-1

see this formula holds good for first order rxns...

i have used

           azoisopropane -------> hexane + nitrogen

at t = 0         P₀                           0                  0

at t =360      P₀ - p                     p                    p

P₀ = 35

total pressure at t =360 s = P₀ + p = 54

p =54 - 35 = 19

so P₀ - p = 16

now use K = ln( P₀ / P₀ - p ) / t