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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 May 2007 16:17:34 IST
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A granulated sample of aircraft alloy (Al,Mg,Cu)weighing 8.72g was first treated with alkali and then with very dilute Hcl,leaving a residue.The residue after alkali boiling weighed 2.10g and the acid insoluble residue weighed 0.69g.What is the composition of alloy?
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tina
Dream what u want to;go where u want to, be waat u want to be, because u have only one life. |
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i think Al is 6.62 g , 1.41 g is Mg & 0.69 g is Cu
is the ans. correct? neways, i think in 1st step all the aluminium will get absorbed coz' it is amphoteric in nature... in 2nd step, all the Mg will be used up coz' acid is dilute & Mg is quite reactive with acids(whereas Cu is not) so remaining is Cu...
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27 May 2007 16:34:42 IST
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I know that. a+b+c=8.72 b+c=2.10(residue after alkali boiling) i cannot understand this step. How could this be the residue after alkali8 treatment as al reacts with alkali to give aluminate . a should be used inside of b.
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tina
Dream what u want to;go where u want to, be waat u want to be, because u have only one life. |
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27 May 2007 16:38:19 IST
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what do you mean "a should be inside b" ???
just consider that after reacting with alkali, the unreacting part is taken out, so residue is 2.10g....
ask me if you've not understood...
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27 May 2007 17:07:37 IST
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Sorry, it was a typing mistake i meant instead of b. Yes i got the point. Anyways thanks
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Be like a postage stamp.Stick to anything until you get there.
Sulekha |
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27 May 2007 17:12:05 IST
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if a means Al then a is only getting used in 1st step...
plz specify what's a,b,c...
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27 May 2007 21:53:29 IST
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hey! but you didn't give me any rate?!?!?! 
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28 May 2007 21:32:46 IST
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rating for u r answer happy cheers
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tina
Dream what u want to;go where u want to, be waat u want to be, because u have only one life. |
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