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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 16:31:24 IST
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hat velocity should a proton have to have same debroglie wavelength of an electon if the velocity of an electron is v
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 16:38:57 IST
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By the problem, wavelength = h / (mass of proton x vel. of proton ) = h / ( mass of electron x vel. of electron ) i.e velocity of proton = v x (mass of electron) / (mass of proton) = v / 1836 ( since mass of a proton is approx. 1836 times heavier than an electron) Ans: v /1836
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2007 21:21:25 IST
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De broglie wavelength of a particle is given by  = h/p where  = debroglie wavelength p = mv = momentum of the given particle. Now mass of electron = me velocity of electron = v corresponding to which wavelength of electron is = e= h/ m ev let proton velocity = v' mass of proton = 1836 me so proton wavelength = p = h /1836m ev' for e = p or h/ mev = h /1836mev' or v' = v/1836 is the required velocity of proton.
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