IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

srujana

An electron is accelerated by a P.D. of 1000 volts. Calculate its de broglie
wavelength

Calculate the wavelength of X rays emitted, when this electron strikes a solid

Mr.IITIAN007

Well the De-Broglie wavelength is approximately (taking significant figures in consideration) 0.389 x 10 to the power -10 metre or simply 0.389 Amstrong.
It is just the formula Srujana ...h / root over 2 m e V ....where
m=mass of electron in kg
e=charge of electron in Coulombs
V= p.d given
h=Planks constant
Now I hate to ask this ....but please rate me .

joyfrancis

Potential is defined as the energy per unit charge.

if potential=V and charge=e ; Energy=eV

By energy conservation eV=mv^2/2

= (1.6*10^-19)(1000)=(9.1*10^-31)v²/2

= v=18.7*10⁶

De Broglie wavelength = h/mv

= (6.6*10^-34)/(9.1*10^-31)(18.7*10⁶)

= 0.38 A

aravindh_ramaswamy

The answer for the first question is 0.3868 angstrom.

and the answer for the second question is 392.13 angstrom.(

=12400/

V angstrom)

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