Henry"s law constant for the molality of methane in benzene at 298 K is 4.27 x 10⁵ mm Hg.Calculate the solublity  of methane in benzene at 298 K under 760 mm Hg?

solubility = henry constant *  pressure ..

just multiply the  two terms and get ur answer

someone answer this question. rate assured

Kh = 4.27 x 10^5

P = 760mm

solubility means mole fraction

we knw dat

p= kH x

x = p/Kh = 760/4.27 x 10^5

u'll get

1.77 x 10^ -3