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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: double bond equivalents
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Nithy (400)

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Hi!
 
could anybody pleaseeeeeeeee explain how to find double bond equivalents for
 
C13H10BrNS
 
C3H8N+
 
 

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Nithy (400)

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sorry! should have posted it in organic chemistry.
 
somebody please ans
u will defenitely get rated
 

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tarun007 (115)

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hi nithy!!

to find double bond eq:
1) replace Br as H (halides r equi to H in terms of bonds to C reqd)
2)N by .5 C
3)n jus remove S or O as it is (as it does not effect no of double bonds)

the resultant comp will be: C13.5H11
when dere r no double bonds in a hypothetical compound wid 13.5 carbon atoms then no of H atoms r=29
diff of H atoms=18
no. of double bonds=18/2=9

henc the ans is 9

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joyfrancis (1504)

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Let there be any compound of the form CaHbXcNdOe then the double bond equivalent is written as
( a + 1 ) - ( b + c - d ) / 2.
 
The double bond equivalent does not depend on the oxygens.
 
1 dbeq = 1 double bond = 1 ring.
 
If dbeq >= 4 then the compound is benzene or it's derivative

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Nithy (400)

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I am very confused!!!!!
 
why should u replace N by 1.5C??
why doen't O affect double bond????
i don't get the ans by Joyfrancis's method.
 
somebody help!
and also ans Q2

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tarun007 (115)

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sry yaar did 1 mistake:
N shud be replaced by half a carbon atom
so i have edited my previous reply........

reason: in an org comp if we want to insert a N atom inside (ie the N shud not be at the end of the chain) its chain then no of H atoms reqd is 1 (ie half of 2) n dat for C is 2

no of S atom is equi to 0 carbon atom coz if we wanna insert it in the org comp chain then the no of H atom reqd is 0 .


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