5 G OF A SILVER COIN WAS DISSOLVED IN DIL.HNO^3 AND THEN AGCL PRECIPITATED FROM IT .IF THE MASS OF AGCL WAS FOUND TO BE 5.98g.CALCULATE %OF AG IN THE COIN?
the amt of AgCl ppted is 5.98gms which is (5.98/143.5)mols of Ag in AgCl so the wt of Ag will be (5.98/143.5)*108 gms. from this we can find the % comp.
the amt of AgCl ppted is 5.98gms which is (5.98/143.5)mols of Ag in AgCl so the wt of Ag will be (5.98/143.5)*108 gms. from this we can find the % comp.