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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Feb 2007 16:29:42 IST
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The standard electrode potentials of Zn2+/Zn and Ag+/Ag are --0.763& +0.763 respectively.find the standard potential of the cell. I THOUGHT THE ANS IS 0.799+2(0.763) BUT ANS GIVEN IS 0.799+0.763.CAN U EXPLAIN WHICH IS CORRECT?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Feb 2007 16:33:35 IST
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are the conc. given?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Feb 2007 19:51:55 IST
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Hello Trisha, Is your question correct? whether Standard electrode potential of Ag is +0.763 or +0.799. If it be +.799 then; Zn 2+ + 2e- = Zn E0 = -.763V (Oxidation half cell) Ag+ + e- = Ag E0 = +.799V ( Reduction half cell) Zn(s) + 2Ag+ = Ag + Zn 2+ Standard Cell Potential = Standard potential of Cathode - Standard Potential of Anode = 0.799V - (-0.763V) = 1.55V Now what is your doubt? If you're convinced with my answer do not forget to vote me, if not do reply.........
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@seth |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Feb 2007 00:38:59 IST
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anurag has done it nicely, BUT the confusion i think TRISHA has IS that as converting Ag+ + e- = Ag , E0 = +.799V ( Reduction half cell) and note while converting 2Ag+ + 2e- = 2 Ag E0 is ALSO EQUAL TO +.799V RIGHT THEREFORE IN UR ANSWER 2* 0.799 V WAS COMING AS u were also multiplying it, but actually , it remains +0.799V . understood............ right
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BELIEVE IN URSELF.....BECAUSE I BELIEVE IN U.............. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Feb 2007 14:52:41 IST
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Hey DON007, Thanks for supporting my explanation.
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@seth |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Feb 2007 20:55:30 IST
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DON&ANURAG PLZ TELL ME WHY 2Ag + 2Ag 2 is not multiplied for emf?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Feb 2007 16:01:46 IST
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The emf is not like energy that has to be multiplied. When a reaction is added, subtracted or multipliedor divided then same operation can be applied to energy but not emf. Hence we have to use the formula  G= -nFE n= n-factor F= 96500 C E= EMF
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In emf calculations emf is energy change per unit charge. So it is energy change per electron for silver as well as zinc. So you are not reruired to multiply Ag potential by 2.
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Feb 2007 12:31:49 IST
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thanks
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