IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

kvenkan

to bring electron from infinity to nucleus , their energy increases towards

a)more positive value

b)more negative value

c)less positive value

d)less negative value

joyfrancis

energy in a shell is given by
-13.6(Z^2/n^2)
if n=infinity the energy becomes zero, if n=1 it is -13.6, so this way the energy increases more on the negative side while bringing the electron from infinity to the nucleus.

aankurverma

formula is

-13.6*z^2/n^2eV

hence as n

E

1/n^2

so energy will increase towards -ve

rate me if i m right

i think i m correct

subs

delU = -_[

_]

^{[ r]} kze^₂r^-2 dr

hence

delU = kze²/r

hence it is delU is +ve

kvenkan

r u sure

subs

Couloumbs law can be applied to the system of the nucleus and the electron

aankurverma

ya dear sure 100%

rate me pls

arun-rashi

maximum energy of any electron is zero at infinity so as we go towerds nucleus negative value increases means energy decreases so stability increases.as we go far from nucleaus energy increases so stability decreases.

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