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varsha valli g.'s Avatar
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Joined: 31 Jan 2007
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21 Apr 2008 11:20:33 IST
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ENergy of orbitals!!!!!!!!!!!!!
None

in atomic structure,
 
1)  if n = 4, l = 0,
2)  if n = 3, l = 2
which has more energy?
by using bohr-burry rule 2) has more energy, but if we see the quantum no. 1) has more energy.
 
Confusing!!??
 
which one should we use & which is the right answer?
!!!!!!!!!!!!!
 


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Ashwini's Avatar

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Joined: 4 Nov 2007
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21 Apr 2008 15:26:00 IST
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actually, 4s and 3d orbitals have energy quite near to each other
but since we remove the electrons  first from 4s and then 3d, i think 4s has more energy..
 

Cool goIITian

Joined: 4 Feb 2008
Posts: 69
21 Apr 2008 15:34:03 IST
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n=3 l=2 will haVE MORE ENERGY BECAUSE 3+2 IS 5
n=4 l=0 will have less energy as 4+0 is 4
pinnacle's Avatar

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Joined: 16 Aug 2007
Posts: 176
21 Apr 2008 15:36:45 IST
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m kinda agreein wid d both of abv posts :P
but i ll say its 3d which has more energy
srinath's Avatar

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22 Apr 2008 08:56:24 IST
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Use the ( n + l ) rule .
If the value of ( n + l ) is same , then look at the value of n , greater value of n , impiles a greater energy .
here ( 4 + 0 )  = 4
       ( 3 + 2 ) = 5
then , energy value of 3d is more.
 
rohit's Avatar

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Joined: 24 Jan 2008
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22 Apr 2008 09:05:49 IST
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yup
3d has more energy
see while filling the orbitals the one with lowest energy is filled first
now we know that 4s is filled first followed by 3d
so the answer is 3d

and u can also check it by using n+l rule as other have said

and regarding the removing of e it is first remove from 4s( as all know)  coz the removing is done from outermost orbit
as 4s is the outermost orbit compared to 3d, the e is first removed from it
Akshay Pamnani's Avatar

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Joined: 27 Nov 2007
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22 Apr 2008 10:22:46 IST
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No 4s has more energy,the n+l rule that we use is exactly valid only till 20 atomic number,thats why we remove electron from 4s first



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