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kusum

For the given equlibrium ,

L_gM_gthe k_f=5*10^-4 mole/litre/seconds and

k_b= 3*10^-2 litrere/mole/seconds , then find the equlibrium concentration of M .

NOTE :ANSWER DOES EXIST FOR THIS PROBLEM

rahul_c

rate of a reaction = k [a]^n

where n is the order

forward reaction is 0 order and back ward reaction is 2nd order

for a 0 order reaction rate = k [a]^0

for 2nd order reaction rate =k[a]^2

let equilbrium concetration of M be x and 1-x due to backward reaction

for forward reaction rate =kf

for backward reaction rate = kb [ x/(1-x)]^2

at equilibrium , rate of forward reaction = rate of backward reaction

kf /kb = [x/ (1-x) ]^2

x = 0.114

0.114 M is the equilibrium concentration of M

arun-rashi

if we apply formula for constant mole /lit time ^ - calculate order of reaction for foreward and beckward reaction forward is zero order while backward reaction is 2 order.at equilibrium both rate r equal so calculate concentration.

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