| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Nov 2007 22:21:36 IST
|
|
|
please explain the effect of addition of inert gas at constant pressure to the equilibrium PCl5 = PCl3 + Cl2
|
"I a universe of atoms.......an atom in the universe" |
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Nov 2007 22:28:22 IST
|
|
|
AT CONSTANT VOLUME, ADDN OF INERT GASES DOES NOT CHANGE THE MOLAR CONC OF REACTANTS AND PRODUCTS. SO, EQULIBRIUM IS UNAFFECTED. BUT AT CONSTANT PRESSURE ADDN WILL INC THE VOL, SO MOLAR CONC WILL DECREASE SO THE DISSOCIATION INCREASES AND REACN PROCEEDS IN FORWARD DIRECTION. RATE ME IF IM RIGHT!!!!!
|
Remember Cedric. Remember, if the time should come when you have to make a choice between what is right and what is easy, remember what happened to a boy who was good, and kind, and brave, because he strayed across the path of Lord Voldemort. Remember Cedric Diggory.
Albus Dumbledore
Goblet of Fire, Chapter 37, Page 724
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Nov 2007 22:36:36 IST
|
|
|
BUT THE MOLAR CONCENTRATION OF REACTANTS AS WELL AS PRODUCTS FALL..... SO HOW DO I KNOW WHICH SIDE THE EQUILIBRIUM SHIFTS?
|
"I a universe of atoms.......an atom in the universe" |
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Nov 2007 22:49:21 IST
|
|
|
right shift
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Nov 2007 22:50:27 IST
|
|
|
whichever side has more moles, the reaction proceeds in that direction if pressure is increased. here left side - one mole right - 2 moles
|
---------------------------------------------------------------
- Gaurav Ragtah (spideyunlimited)
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Nov 2007 22:58:11 IST
|
|
|
not clear.... can u plz explain in detail
|
"I a universe of atoms.......an atom in the universe" |
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Nov 2007 23:03:02 IST
|
|
|
there is only one mole in PCl5 and on the LHS there are 2 compounds hence 2 moles so right shift
as..........whichever side has more moles, the reaction proceeds in that direction if pressure is increased. here left side - one mole right - 2 moles
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Nov 2007 23:05:07 IST
|
|
|
here pressure is constant
|
"I a universe of atoms.......an atom in the universe" |
this reply: 10 points
(with 2 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Nov 2007 23:10:46 IST
|
|
|
oops
ANS: On Adding inert gas at constant pressure the reaction instantly shifts in the Direction where the Gaseous stoichiometric coefficient is greater!
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Nov 2007 23:14:25 IST
|
|
|
why?
|
"I a universe of atoms.......an atom in the universe" |
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Nov 2007 23:21:17 IST
|
|
|
thats the theory part !
reasonat constant press. volume is increased and summation(ng) also increases. at delta ng is greater than 0 then Q=kc/kp to retain equilibrium Quotient increases.numerator increases ..products increase
hence fwd shift..
thats the best i can do......
plz rate..
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|