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Physical Chemistry

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Joined:	19 Feb 2007
Post:	3834

21 Feb 2007 15:04:18 IST

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624

factors

None

plz tell me how to calculate van't hoff factor

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Kiran H

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Joined: 7 Nov 2006

Posts: 296

21 Feb 2007 15:26:50 IST

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If you have studied colligative properties you'l know that

When a solute dissociates in solution

= (i - 1) / ( n - 1)

When a solute associates in solution

= ( i - 1) / ( 1/n - 1 )

Where

is the degree of association/ dissociation and

n

is the number of particles produced during association or dissociation per molecule or formula unit of the solute.

By knowing n and

we can easily calculate ' i ' ie the vant hoff factor.

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Bipin Dubey

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Joined: 23 Jan 2007

Posts: 7942

24 Feb 2007 13:02:56 IST

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The van 't Hoff factor i is the number of moles of solute actually in solution per mole of solid solute added. Equivalently, i refers to the ratio of true molecular mass to calculated molecular methods by colligative methods.

When solute particles associate in solution, i < 1.
Degree of dissociation

= (i - 1)/(n - 1)

When solute particles dissociate in solution, i > 1.
Degree of dissociation

= [i - 1]/[(1/n) - 1]

Otherwise i = 1.

= 0

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Himanshu

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Joined: 19 Feb 2007

Posts: 3834

24 Feb 2007 13:50:37 IST

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thank u sir & kiran

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