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Physical Chemistry
40 atoms of radioactive element x (t half= 10 hours) r present.how many r likely to remain after 40 hours....
a. 1
b. 2.5
c. 5
d. 3
since radioactivity follows 1st order kinetics so t half should remain constant and by doing dat d ans. which u will get is 2.5........but atoms can't be in fraction (didn't notice dat during exam.....
) so how to proceed in this question?
Comments (10)
Radioactivity is a random phenomena and obeys poisson distribution, the no. of nuclei remaining after given time is just a probability and is average of several 1000's of trials. Thus if no. of moles are 10 and half life is 20hrs, then it does not mean that the no. of moles with reduce to 5 after 20hrs. Rather 5 is the most probable answer and is statistical average of infinite samples. The answer can be either 4 or 6 or someting else, but the important thing is the more you deviate form 5 the probability of that no. of nuclie (remaining undecayed) will diminish and reduce.
Now in your question the answer is 2.5, but since the number of atoms can not be fractional so the next answer lying close to 2.5 is 3
Thus most likely answer is 3 atoms














Hello!!!!!!!
I guess in question..it is talking about moles of atoms..i.e 40 moles are at present..
Half life is 10 hrs..
So after every 10 hr mole will be half..
So 40 hr means 4 half life..i.e amount will be 1/16 or can say 2.5 moles.