IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

srujana

Two flasks of equal volume connected by a narrow tube of negligible volume contains 1 mol of hydrogen gas at 300 K and 0.5 atm, One of the flasks is immersed into a thermostat maintained at 400 K, and the other was maintained at 300 K temperature. Determine, the final Pressure, final amount of hydrogen gas in each flask.

srujana

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akku

initially                                    after the temp change
fr 1st flask                                 fr 1st flask
p=.5atm
t=300K                                        t'=400K

fr 2nd flask                                fr 2nd flask
p=.5atm
t=300K                                         t=300K

hydrogen gas will flow frm i vessel 2 the other till the pressure in both vessels is same
n1+n2=n1'+n2' (total moles of H2 will remain conserve)
pV/t+pV/t=p'V/t+p'V/t'
2p/t=p'(1/t+1/t')
calculate p'
fr the second part just equate pressure in both vessels
n1t1=n2t2
n1+n2=2
n1:n2=3:4
n1=3/7*2
n2=4/7*2
Hence the ans

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