IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

angel.angelina

A LONG RECTANGULAR BOX IS FILLED WITH Cl2 (WT. 35.45) WHICH IS KNOWN TOCONTAIN ONLY 35Cl & 37Cl . IF THE BOX COULD BE DIVIDED BY A PARTITION & THE 2 TYPES OF Cl2 PUT IN 2 COMPARTMENTS RESP. CALCULATE WHERE SHOULD THE PARTITION BE MADE IF PRESSURE ON BOTH SIDES ARE TO BE EQUAL?

animal

I m not cofident still i m trying

PV=nRT

PV₁=n₁RT FOR 35Cl

PV₂=n₂RT FOR 37Cl

NOW ASSUMING THAT BOTH THE GASES HAVE SAME WT.

L₁/L₂=37/35

TELL ME WHERE I M WRONG....

angel.angelina

ANIMAL YOU DID THE SAME MISTAKE LIKE ME . TRY AGAIN YOU R WRONG.

animal

hey angel i m not getting it plz tell the soln.

dream

is it
L1/L2 = 1.018
where L1 is the length on the side of Cl35
and L2 the length on the side of Cl37

krishna.gopal

Let L1 is length of 35 and L2 is that of 37. So number of molecules of 35 (n1) and 37(n2) are proportional to L1/L2
As average molar mass is 35.45
So 35.45= (35*L1+37*l2)/(L1+L2)
Solved this to get L1/L2

animal

yes sir thats right i think

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