IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

smartgoels

1 mole of Fe_0.9 O was dopped by 0.2 mole Ti⁴⁺ ions where Ti⁴⁺ replaced Fe⁺² replaced Fe⁺² in the crystal. this compound is dissolved in 1 litre of water & ten treated with 0.1 KMnO₄ SOLUTION IN ACIDIC MEDIUM. calculate volume of KMnO₄ required in ml

rahul_c

Fe[2+]= Fe[3+] +[e-]

I HAVE TAKEN INTO ACCOUNT THAT Fe[2+] LOSES 1 mole of ELECTRON TO FORM Fe [ 3+]

Fe[3+] CANNOT BE oxidised MORE by KMno4 as it at very high oxidation state

SINCE THE OXIDATION STATE OF Fe IS NOT EXACTLY 2 ELSE IT WOULD HAVE BEEN FeO.SO IT ALS CONTAINS SOME Fe[3+]

LET FOR O.N = 2 NO.OF MOLES BE x

   FOR 1 MOLE
       2x +3(0.9-x)=2 ( O.N=2)
         x=0.7

BALANCING THE CHARGES
       1 MOLE Ti[4+]=2 MOLE OF Fe[2+]

MnO4[-] + 8H[+] + 5e[-]=Mn[2+] + 4H20 { H20=WATER }------(1)
Fe[2+]= Fe[3+] +[e-]

   THEREFORE NUMBER OF MOLES Fe[2+]=(0.7*0.2)/2=0.07
0.07 MOLES IN 1 LITRE=0.O7 M
AS 5 ELECTR0NS ARE INVOLVED IN THE PROCESS
           =0.07/5=O.014 M
NOW ,1 MOLE KMnO4==0.014 MOLE {== EQUIVALENT }
      0.1 MOLE KMnO4==0.14 MOLE
1 MOLE IS IN 1000ML
0.14 MOLE IS IN 140ML

THEREFORE VOLUME OF KMnO4 REQ.D=140 ML

with regards

smartgoels

well my dear titanium do not exist in +3 state well potassium permenganate is an oxidizing agent it will try to increase the oxidsation state of ti. well what about ferric ions

rahul_c

what's the answer ?

rahul_c

i have made the corrections , can you tell me what is the answer?

smartgoels

well you really do ease my problem to a great extent. well i will be really obliged if you cold provide the whole solution

Ask & Discuss Questions with Community & Experts