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Physical Chemistry
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3 Mar 2008 13:37:35 IST
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Q) C(S) + O2 --------------> CO2(g)
H=?
H=?CALCULATE THE
H FOR THIS REACTION ?
H FOR THIS REACTION ?now the data given is
C(S) + 1/2O2(g) ------> CO(g)
H= -26K CAL
H= -26K CALCO(g) + 1/2 O2 ------> CO2(g)
H= -68K CAL
H= -68K CALnow according to the hess law u can get enthalpy change for the reaction by adding these 2 reactions.
there for
H=- 94.0 k cal
H=- 94.0 k cal3 Mar 2008 15:36:24 IST
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When reactions take place, energy in the form of heat is either absorbed (endothermic) or released (exothermic). The amount of heat involved in a reaction depends upon the particular reaction studied or the amount of reactant that is used. Sometimes it is difficult to measure the heat of a reaction directly. Hess?s Law tells us that the amount of heat involved in a reaction is the same, whether the reaction takes place in one or several steps. A modification of this law permits us to find the heat of one step of a reaction if the overall heat and the heats for the other steps are known












try looking at this site:
http://dbhs.wvusd.k12.ca.us/webdocs/Thermochem/HessLawIntro1.html
hope this helps