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junglejalebi

pcl5 at an intial pressure of 1 atm is placed in a closed vessel containing chlorine ata a pressure of 0.2 atm.if pcl5 dissociates to 20% then fond....

partial pressure of pcl5

partial pressure of pcl3

partaial ...............cl2

eqilibrium constant

reply fast plz help me

junglejalebi

plz attempt it

junglejalebi

i think nobody understand this mysterious topic like me

junglejalebi

do ittttttttttttttttttttttttttttttttttttttttttttttttttt

BALGANESH

PCl5 = PCl3 + Cl2

initially let 1 mole of pcl5 be present since degree of dissociation is 20

% .at equilibrium we get

0.8 mole =pcl5

0.2 mole = pcl2

0.2 mole =cl2

total no of moles at equi = 1.2

now partial pressure = mole fraction . total pressure

therefroe pp (partial pressure ) of pcl5 =0.8/1.2 = 2/3

pp of pcl2 = pp of cl2 = 0.2/1.2 = 1/6

now Kp ( eq constant ) = pp of pcl2 . pp of cl2 / pp of pcl5

solving we get Kp =1/24

rate if useful

akshay.khare91

Let one mole of PCl5 is present and it is given that 20% dissociates
then at equilibrium

no. of moles of PCl5 = 0.8
no. of moles of PCl3 = 0.2
no. of moles of Cl2 = 0.2

now partial pressure = no. of mole/total mole * total pressure

using this find partial pressure

and then find Kp

and then using Kp= Kc(RT)^delta n

find Kc......

junglejalebi

baljadesh
ur ans are not maching with te given ones

1..0.8
2.0.2
3..0.4
4..0.10

BALGANESH

they are definitely wrong , u can check my soln there isn't mistake

eistien

hey jungle jalebi baljadesh is rite but the mistake he has commited is that he didnt consider that there is already 0.2 atm of CL2 in the surrounding

so his CL2 answer +0.2 answer gives yours and replace in his equation as 0.2+x for that CL2!!! thats all now am i right jungl jalebi???

eistien

balganesh do you understand your mistake!!! jungle jalebi reply ma!!!

BALGANESH

yeah did not read that thanx

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