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Physical Chemistry

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6 May 2008 19:07:48 IST

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Ionic Equilibrium

None

Find the pH of 10^-6 M CH3CO2H (Ka=1.8 * 10^-5)?

Ans= 6.01

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Akansha

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Joined: 16 Apr 2007

Posts: 663

6 May 2008 19:33:46 IST

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10^-6

CH3CO2H+H20---->CH3C00-+H3O+

10^-6(1-@) 10^-6@ 10^-6@+10^-7

Ka=[CH3C00-][H3O+]/[CH3CO2H][H20]

weak acid can b treated as strong if its so dilute (@wod come around .999 , check frm @=(Ka/C)^.5)

ph=-log(10^-7+10^-6)=6.01

ashish banga

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6 May 2008 19:36:30 IST

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edited

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