sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
 90 chars left    advanced
Ask iit jee aieee pet cbse icse state board experts Expert Question: Kc for a reaction increases with increase in temprature but not for thIS REACTION
Forum Index -> Physical Chemistry like the article? email it to a friend.  
Author Message
Kailash_chandra (0)

New kid on the Block

Olaaa!! Perrrfect answer. 0  [0 rates]

Kailash_chandra's Avatar

total posts: 2    
offline Offline
2NO + O2= 2NO2
WHY?
    
priyesh (1586)

Blazing goIITian

Olaaa!! Perrrfect answer. 256  [409 rates]

priyesh's Avatar

total posts: 1032    
offline Offline
hi
value of equilibrium constant does not always increase with increase in temp
 
value of equilibrium constant increases with increase in temp only when reaction is endothermic
 
& it will decrease with increase in temp if the reaction is exothermic  
 
now ur reaction
i.e
2NO + O2= 2NO2 is exothermic & hence with increase in temp the equilibrium constant decreases.
 

"Imagination is more important than knowledge."
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
catch_arnnie (521)

Blazing goIITian

Olaaa!! Perrrfect answer. 81  [139 rates]

catch_arnnie's Avatar

total posts: 444    
offline Offline
the only reason i can think of is that the reaction might be endothermic in the backward direction so, Kc does not increase on increase in temperature...

plz correct me if i'm wrong...

PLEASE RATE MY ANSWERS IF YOU FIND THEM USEFUL...
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
iitkgp_bipin (5892)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 1004  bad job dude!! I dont approve of this answer! 1  [1442 rates]

iitkgp_bipin's Avatar

total posts: 4084    
offline Offline
Relationship between equilibrium constant K, standard heat of reaction H0 and temperature T is :

ln(K2/K1) = (-H0/R)(1/T2 - 1/T1)

If the reaction is endothermic  H0  > 0, hence K increases  with the increase in temperature.

If the reaction is exothermic,  H0  < 0, hence K decreases with the increase in temperature.



Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur

 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
priyesh (1586)

Blazing goIITian

Olaaa!! Perrrfect answer. 256  [409 rates]

priyesh's Avatar

total posts: 1032    
offline Offline
hey bipin sir the equation u have written is wrong(as u have got an extra - sign) & thus the result u have obtined is also wrong(just the opposite to actual)
 
see
ln(K2/K1) = - H(1/T2 - 1/T1)
now taking - sign out from
(1/T2 - 1/T1) the two - sign get canceled & we get
ln(K2/K1) = H(1/T1 - 1/T2)
ln(K2/K1) = H((T2 - T1)/T1T2)
hence if reaction is endothermic then increase in temp will increase the equilibrium constant
& if reaction is exothermic the equilibrium constant decreases with increase in temp
 
Cheers
 
 

"Imagination is more important than knowledge."
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
 
Forum Index -> Physical Chemistry
Go to:   

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya