hey bipin sir the equation u have written is wrong(as u have got an extra - sign) & thus the result u have obtined is also wrong(just the opposite to actual)
see
ln(K2/K1) = -

H(1/T2 - 1/T1)
now taking - sign out from
(1/T2 - 1/T1) the two - sign get canceled & we get
ln(K2/K1) =
H(1/T1 - 1/T2) ln(K2/K1) =

H((T2 - T1)/T1T2)
hence if reaction is endothermic then increase in temp will increase the equilibrium constant
& if reaction is exothermic the equilibrium constant decreases with increase in temp
Cheers