other wise we can only solve it using the approximation that ethanol's volume is not considered. let there be i mole of sol. so moles of ethanol=.04 and moles of water = 1-.04=.96 so mass of water=.96x18=17.28 gm vol of water=17.28 ml=.01728 lit. molarity= moles of solute/vol. of sol. = .04/.01728= 2.31M