IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

witty_rocket

what is the mass of 3.0115*10

23 atoms of white phosphorous

sid_2222000

i feel both will be alost equal........but a.m.u assinged on the basis of BE will be slightly larger than tht of c12 as the binding energy(per nucleon) of c is greater than that of be...........hence more will be the mass converted ta energy ..........hence lessr the mass per nucleon......therefore lessr the amu(on basis of c12)...............hence amu on basis of BE will be more than tht of c12

witty_rocket

but can u tell me on the basis of amu

edison

Nuclear masses are measured in terms of atomic mass units with the carbon-12 nucleus defined as having a mass of exactly 12 amu. It is also common practice to quote the rest mass energy E=m₀c² as if it were the mass.

or

a.m.u is also defined to be one twelfth of the mass of an unbound atom of the carbon-12 nuclide, at rest and in its ground state.

1 u = 1/N_A gram = 1/ (1000 N_A) kg (where N_A is Avogadro's number)

1 u = 1.660538782(83) × 10^-27 kg = 931.494028(23) MeV/c²

Since, for berillium amu is 9.012 > 9, so amu based on Be-9 would be slightly larger than amu based on C-14.

witty_rocket

Na2[Fe(CN)5NO]

what is the oxidation state of iron in this compound?

umang

Hey !

The O.N. of iron is +2 . This is as follows -

As the compound is neutral , therefore , balancing the charges -

1*2 + x + (-1)*5 + 1 = 0

solve and get x = +2 .

I hope u hav understood !!!

witty_rocket

what is the mass of 3.0115*10

23 atoms of white phosphorous

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