IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

saharnyasdev

In the case of an ideal gas ,at 27.C and 1 atm pressure ,the average volume available for each molecule is......

rohitkuruvila

P=1 atm,T=300 K

use PV=RT(For 1 mole of the gas)

V=(RT)/P

V=(0.0821*300)/1

V=24.63 litres

1 mole of an ideal gas occupies 24.63 litres at 300 K

i.e.6.023*(10^23)molecules occupy 24.63 litres

1 molecule occupies 'x' litres

x=(1*24.63)/[6.023*(10^23)]

x=4.0893*[10^(-23)]litres

1 molecule occupies 4.0893*[10^(-23)]litres