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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Jul 2007 20:42:46 IST
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As per Bohr's theory ,
ang momentum = nh/2pi ( where n is principal quantum no)
But
ang momentum = root(l(l+1) * h/2pi
when an elecron is in 1s orbital
by first eqn
ang mom = h/2pi
by second eqn
ang mom = 0
which is correct?
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10 Jul 2007 21:20:32 IST
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the first one is the ANGULAR momentum of the electron moving
in an atom about the centre,NUCLEUS. we derive it as : m*v*r here r is distance from nucleus.
the second one is the ORBITAL angular momentum.
THEY ARE NOT THE SAME.
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10 Jul 2007 21:26:36 IST
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plzz. rate if it helps
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
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<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
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10 Jul 2007 21:37:20 IST
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Sure i am that this day we are the masters of our fate, that the task set before us is not above our strengths; that its pangs and toils are not beyond our endurance. As long as we have faith in our own cause and an unconquerable will to win, victory will not be denied us.
- Winston Churchill |
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10 Jul 2007 21:41:23 IST
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nh/2pi is the angular momentum of the electron in the nth orbital while root l(l+1) is the momentum of the orbital.
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10 Jul 2007 23:58:16 IST
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I think Nikhil is correct.
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orbital anguler momentum related with orientation of orbital .this is expressed by the formula h/2  l(l+1) here l is azumithal quantum number or secondary quantum number or subsidary quantum number.for S l=0 so for S orbital anguler momentum is zero so no orientation of orbital means it present equally on three axis.for Porbital there is value of anguler momentum so it has specific orientation at three axis.anguler momentum of orbit is derived by second postulate of bohrs theory ,mvr =nh/2pi mis mass of electron,v is velocity,r is redius of atom,n is number of shell,h is planks constant for example if we calculate anguler momentum of P orbit this is 6h/2pi
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Arun / Rashi - Authors Macromind MCQ of Chemistry from G.R Batla |
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