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witty_rocket

1 mole N2H4 looses 10 mole electron to form new compound x .assuming that all nitrogen appears in the new compound, what is the oxidation state of N in x.

given that o.s. of hydrogen remains unchanged.

witty_rocket

plz reply to the question

mh_harsh

N₂H₄,

X

here in N₂H₄the O.N. of H is -4 and that of N is +4

when X is formed N looses 10 electrons so the net charge on N₂ =+4-10= -6

since 1 molecule of N has 2 atoms so one atom has - 6/2=- 3 ON

hence N has -2 ON

mh_harsh

N₂H₄,

X

here in N₂H₄the O.N. of H is -4 and that of N is +4

when X is formed N looses 10 electrons so the net charge on N₂ =+4-10= -6

since 1 molecule of N has 2 atoms so one atom has - 6/2=- 3 ON

hence N has -2 ON

krishna.gopal

In this compound oxidation state of N is -2. On loss of 5 electrons per atom it will become +3

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