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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Physical Chemistry
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K4FECN6 (102)

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1.Why is it necessary to remove CO when ammonia is obtained by HABER'S process?
2.What is the role of desorption in the proces of catalysis?
3.What modification can be done to HARDY-SCHULZE law?(NCERT Part1 Pg-145)

ANAND KRISHNAN
    
nandithac (86)

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the reactant molecules which gets adrorbed on the surface of the catalyst for the reaction products to be formed needs to be removed after formation of the products for further reaction to take place this is accomplished by desorption
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kasirajan.1990 (1349)

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1. NH3 is removed to avoid the reverse rxn in habers process.

2.desorption makes the surface available again formore rxnz to occur.

3. c this
http://www.goiit.com/posts/list/physical-chemistry-what-modifications-can-u-suggest-on-hardy-44221.htm


kasirajan



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Aatish (2288)

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hey Kasiranjan I agree wid you for the 2nd and 3rd ones........

BUT for the 1st one.......I have not seen any CO coming out in HABER's PROCESS.......

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There's Light at the end of every Tunnel, so KEEP MOVING....
Best of luck to all my mates....
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Aatish (2288)

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That must be Ammonia.....which is taken out.......

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There's Light at the end of every Tunnel, so KEEP MOVING....
Best of luck to all my mates....
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kasirajan.1990 (1349)

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yup ts ammonia...i hv changed it.

kasirajan



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punnima (563)

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i think its this:
The hydrogen 4 d NH3 synthesis was made by d water-gas process (a Carl Bosch invention) which involves blowing steam through a bed of red hot coke resulting in d separation of hydrogen from oxygen. The nitrogen was obtained by distillation of liquid air, then by cooling and compressing air.

These days, the hydrogen is produced by reforming light petroleum fractions or natural gas (methane, CH4) by adding steam:
CH4(g) + H2O(g) Ni catalyst CO(g) + 3H2(g)
---------->
700*C


Enough steam is used to react with about 45% of the methane (CH4), the rest of the methane is reacted with air:
2CH4(g) + O2(g) + 4N2(g)
(air) Ni catalyst
---------> 2CO(g) + 4H2(g) + 4N2(g)


All the carbon monoxide (CO) in the mixture is oxidised to CO2 using steam and an iron oxide catalyst:
CO(g) + H2O(g) iron oxide catalyst H2(g) + CO2(g)
------------------>

The carbon dioxide (CO2) is removed using a suitable base so that only the nitrogen gas (N2) and hydrogen gas (H2) remain and are used in the production of ammonia (NH3).

VARSHA KRISHNAN....
------------------------------------
IIT is always a word which rises E thru' d body. But 2 achieve it U hav 2 drain out d entire E out of the body....

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punnima (563)

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since it is Haber-Bosch process for producn of ammonia
so it must b removal of CO2 nd not CO

VARSHA KRISHNAN....
------------------------------------
IIT is always a word which rises E thru' d body. But 2 achieve it U hav 2 drain out d entire E out of the body....

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paddy.dude (1028)

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this is so becoz CO acts as a poison and reduces the activity of the catalyst........so it is removed
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