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ANUBHAV SURI's Avatar
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3 Mar 2008 20:34:47 IST
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64g of a organic compound has 24g of C and rest hydrogen & oxygen
find d empirical formula ????????????/


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ashwin menon's Avatar

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3 Mar 2008 20:38:10 IST
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CH3CHO
ANUBHAV SURI's Avatar

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3 Mar 2008 21:22:55 IST
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buddy your answer is wrong
LAMPARD's Avatar

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3 Mar 2008 21:24:06 IST
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Is it C64H321O8?If yes,den i'll post soln..
ANUBHAV SURI's Avatar

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3 Mar 2008 21:25:25 IST
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sorry dude u too r wrong
ERAGON007's Avatar

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3 Mar 2008 21:31:39 IST
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is it C6H12O7
dev_22oct's Avatar

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3 Mar 2008 21:35:24 IST
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ans is CH4O
ANUBHAV SURI's Avatar

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3 Mar 2008 21:35:48 IST
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let me give d choices

C2H8O2
CH4O
C2H4O
CH2O

whatever b ur ans. plz. give d explaination whether not in d choices
dev_22oct's Avatar

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3 Mar 2008 21:37:00 IST
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bt dude your question is not complete its 24g carbon and 8g hyrogen and rest is carbon.....js check it again...i think u have taken it from op aggarwal.
ANUBHAV SURI's Avatar

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3 Mar 2008 21:37:15 IST
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yes dev. plz gimme d explaination
ANUBHAV SURI's Avatar

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3 Mar 2008 21:38:39 IST
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i had found it in an online test @engineerprep
iberis's Avatar

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3 Mar 2008 21:47:51 IST
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it'll be CH4O.
 
you have 24g Carbon in 64g of the compound ie. 2-C. n rest is O and H.  O will be minimum 16g. remaining will be H (64-24-16= 20).  20 H with 2C is not possible. so there has to be one more O. thus remaining H will be 64-24-32=8.
 
thus it'll be C2H80. n the empirical formula will be CH4O.
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3 Mar 2008 21:48:53 IST
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Element    %       At.Wt         Rel. no. of atom        Simplest ratio
  C         37.5        12              37.5/12=3.125         3.125/3.125=1

  H         12.5         1                12.5/1=12.5            12.5/3.125=4

  O          50           16              50/16=3.125            3.125/3.125=1


Thus,emperical formula =CH4O
Hope u got it...
sry fr de wierd ans. above...
ANUBHAV SURI's Avatar

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3 Mar 2008 21:57:01 IST
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yar i m confused to how v can take d mass of oxygen to b 16g
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3 Mar 2008 21:58:13 IST
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wats confusing in dat?mass of O is 16...mass of O2 is 32....
ANUBHAV SURI's Avatar

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3 Mar 2008 21:59:47 IST
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it is not given dat mass of oxygen present is 16g
ashwin menon's Avatar

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3 Mar 2008 22:01:40 IST
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ooopps!!...sorry .made a small mistake..  
and ya..mass of oxygen is taken a s16..
ANUBHAV SURI's Avatar

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3 Mar 2008 22:09:35 IST
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u r not understandin my problem dat v will take mass of O2
to b 16g only if it is given dat d percentage of o2 is 25% or
50%.but here it is not given
iberis's Avatar

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3 Mar 2008 22:25:33 IST
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See, consider a compound containing C,H,O with molecular wt. 64. if  the weight of C in it is 24, then we can say 2-C are present. n rest 40g is O and H. If 1-O is present weight of H remaining will be 24. which is not possible for a compound containing 2C. so we include 2O. thus remaining H will be 40-32=8.
its formula will be C2H8O2 n simplest will be CH4O.
ashwin menon's Avatar

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3 Mar 2008 22:30:28 IST
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@effort..we r not taking O2 as a GAS here.. here its just an oxygen atom.. so it cant have much deviation frm it weight of 16...



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