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Physical Chemistry
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6 Apr 2008 21:44:33 IST
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sorry for the late reply
d----density=1.25g
d=m/V
volume of water can b taken as 1000ml
m=1.25*1000g
in 1000g of water there is 92g of Na+
thus in 1.25*1000g------->1.25*92
substituting the values,
molality=1.25*92*1000/23*1.25*1000
=92/23=4m
hope this helps
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d----density=1.25g
d=m/V
volume of water can b taken as 1000ml
m=1.25*1000g
in 1000g of water there is 92g of Na+
thus in 1.25*1000g------->1.25*92
substituting the values,
molality=1.25*92*1000/23*1.25*1000
=92/23=4m
hope this helps
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