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Xavier4 (4)

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If the density of lake water is 1.25g/mL and
 
contains 92 g of Na+ ions per kg of water ,
 
calculate the molality of Na+ ions in the
 
lake?
    
varshavallig (798)

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is it 4m ???????
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Varsha
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rahulraj1 (14)

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Yes but please explain the process.Is it related to given density.
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Xavier4 (4)

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Please reply soon
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varshavallig (798)

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sorry for the late reply
d----density=1.25g
d=m/V
volume of water can b taken as 1000ml
m=1.25*1000g
in 1000g of water there is 92g of Na+
thus in 1.25*1000g------->1.25*92
substituting the values,
molality=1.25*92*1000/23*1.25*1000
=92/23=4m
hope this helps
!!!!!!!!!!!!!!

Varsha
be cool,
tomorrow is what we make it today,
so if u can dream it , u can make it .
life is an ice cream ,eat it before it melts away!!!!!!!!!
varsha

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Xavier4 (4)

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Is it neccesary to take the volume 1000mL?Can't we take another volume?
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dream (571)

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u can take any other volume it wont affect the final answer
but generally we choose no such that they reduce our calculations
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