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[Post New]17 Apr 2008 20:05:21 IST
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ssbrightstar1 (5)

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The water vapour pressure at 293 K is
 
2338 Pa and the vapour pressure of an
 
aqueous solution is 2295.8 Pa.Determine
 
its osmotic pressure at 313 K if the solution
 
density at this temperature is
 
1010kg/m3.The molecular weight of the
 
solute is 60.
    
[Post New]18 Apr 2008 21:16:30 IST
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ssbrightstar1 (5)

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please reply me
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[Post New]30 Apr 2008 23:09:24 IST
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krishna.gopal (2399)

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mole fraction of water = 2295.8/2338 = 0.982
so mole fraction of solute = 0.018
So there is 0.018*60 g solute per 0.982*18 g water
So 1 liter solution contain 58.16 gram solute
So molarity = 0.97
Use this to find osmotic pressure
Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
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