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Physical Chemistry

Scorching goIITian

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2 Feb 2007 14:29:22 IST

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please tell me about law of mass action.

None

please tell me more about law of mass action in chemical equilibrium.........

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Marshall Eriksen

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2 Feb 2007 23:31:02 IST

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A + B (in eq) C + D
K = [C] [D] / [A] [B]
where k is the equilibrium constant
its the ratio of the active concentration of products to that of the reactants
Active ratio is mols/litre

this is the basic stuff......if u need more ask

sneha kulkarni

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4 Feb 2007 10:47:45 IST

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please tell me more about this..................

please........................

please...............................

arun-rashi

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4 Feb 2007 10:53:14 IST

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this is given by gouldberg and waages according to this active mass of reacting substance means moler concentration in homogeneous chemical reaction is directly praposnational to velocity of reaction,for reversable rection velocity of forward and backward reaction both r there at dynamic eqilibrium both r equal so v1 = v2 Kc=[product]/[reactant] for example N2 +3H2 gives 2NH3 so Kc =[NH3]2/[N2]/[H2]3 for hetrogeneous equlibrium active mass of solid substance is always unity .

sneha kulkarni

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4 Feb 2007 10:59:03 IST

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sir..................how the active masses for gases are expressed? is it in partial pressures?

Marshall Eriksen

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4 Feb 2007 11:22:35 IST

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active mass is moles/litre if i am not wrong

sneha kulkarni

Scorching goIITian

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4 Feb 2007 11:44:07 IST

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you are absolutely right...............but what about gases?

CyBorG

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4 Feb 2007 11:46:47 IST

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It is partial pressure for gases.

schrodinger

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4 Feb 2007 12:12:08 IST

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yes kab is right
for gases we take partial pressure

sneha kulkarni

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4 Feb 2007 21:07:03 IST

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thank you all...........

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