IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

Utsav55

1) Correct set of 4 Quantum numbers of a 4d electron.
The answer is 4,2,1,0

Plz explain how this is the answer, the spin (m) = 0??
n=4 ----- OK
l=o to n-1 ie 0,1,2,3 but its 2 in the answer.

2) The first emission line of Balmer series in H spectrum has the wave number equal to:
The answer is 7R/(144)

ashish_banga

spin should be either +1/2 or -1/2

and answer to the second should be 5R/36

danny_007

l for a d subshell = 2

Utsav55

yes, l = 2 for d.
But how is that 1,0 in the answer 4,2,1,0??

In the 2nd question, what formula to be used to what should be the value of n1 and n2 ??

deedee

wavenumber=1/wavelenght =Rh*z^2(1/n1^2 -1/nz^2)

Utsav55

OK
2nd question solved.

How about the first question??

deedee

for s l=0

for p l=1

for d l=2

n so on

Utsav55

yes, that I know but how the answer can be 4,2,1,0 ??

dev_22oct

this ans is not correct.

ans is 4,2,1,-1/2 or +1/2

becoz for 4d n=4 and l(azimuthal quantum no ) = 2(for d)

m can have values -l to+l including 0.

so m can have ne value frm -2,-1,0, +1,+2

and spin w'll have either +1/2 or -1/2

dev_22oct

2) ans is 5R/36...

i knw that ur doing these questions frm opagarwal..so plzz check the ans properly..the ans that i and the people are giving is correct

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