Hi,
Look,
Consider the initial mass of compound to be 100 gms
So, Xe is 67.2 gms and O is 32.8 gms
now,
Moles of Xe = 67.2 / 131.3 = 0.511 moles
Moles of O = 32.8 / 16 =2.05 moles
So, we get, Xe0.511O2.05
divide the subscripts by 0.511
We get, XeO4.01 = XeO4
This is the empirical formula of the required compound..