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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2007 19:32:51 IST
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What % of sample of nitrogen must be allowed to escape if its temperature, pressure and volume are changed from, 327 C , 3 atm, 2 L to 227 C, 0.6 atm , 1 L respectively
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God has given you one face, and you
make yourself another.
~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2007 19:40:09 IST
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wats the ans ????? is it 12%
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2007 20:26:13 IST
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Answer is not provided. How can the result be 12%?
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God has given you one face, and you
make yourself another.
~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2007 20:40:19 IST
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Find the initial number of moles and the final number of moles.The % decrease is the same as the required %.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2007 20:44:38 IST
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can u xplain the procedure? wat is the significance of the change in temperature and volume and pressure given there?
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~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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P1V1/n1T1 = P2V2/n2T2 THEREFORE 3 * 2/n1600 = 0.6 * 1 / 500 n2 on solving n2 = 0.6n1/5 as n2(MOLES REMAINING) < n1 (MOLES PRESENT INITIALLY), some gas must be allowed to escape = n1-n2= 4.4n1/5 n1 can be found by using PV =nRT ND THE PERCENT OF GAS ESCAPED IS 4.4n1/5n1 *100 = 88%
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