IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

santosh05

40 percent of a mixture of N2 and H2 of .2 and .6 moles respectivly reacts to form NH3.......find no of moles oF nh3,,,,,IS IT ..16 OR .08??

BALGANESH

total no of moles = 8

40% = 3.2 moles of the mixture

now this 3.2 moles of mixture contain 0.8 mole of N2 rest H

N2 + 3H2 = 2NH3

now 1 mole ofN2 reacts with 3 mole of H2 therefore 0.8 mole of N2 will react with 2.4 mole of H2 which is present

therefore from the reaction 1mole N2 = 2 mole of NH3

0.8 mole of N2 = 1.6 mole of NH3

varshavallig

@ BALGANESH
it is 0.2 and 0.6 moles not 2 and 6.
so the ans is 0.16 moles
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