IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

sonal_01

The reaction in which the yield of the product

cannot be increased by the application of high pressure is

(a) PCl 3 (g) + Cl 2 (g) ----reversible sign------>-PCl 5 (g)

(b) N 2 (g) + O 2 (g)-------r-> 2NO (g)

(c) N 2 (g) + 3H 2 (g)-----r--> 2NH 3 (g)

(d) 2SO 2 (g) + O 2 (g) ---r-->2SO 3 (g)

r=reversible reacn arrow

giv explaination

indr12365

Hi sonal,
The product yeild of any reaction involving gaseous reagents can be increased by application of pressure if it involves a decrease in no of gaseous moles.
This follows from Le chatlier's principle.
The eqm simply shifts to the direction involving less no moles of gaseous products
Now clearly,reaction 2 has no change in no of moles--->no of mol products-no of mols of reactants=0.
Virtually this reaction eqm is not affected on changing the pressure except tat eqm is attained at a faster rate.
All others proceeds to a decerase in no of mols of products hence favoured by increase in P.
Ans (b)
Hope it's ALLCLEAR..!!!...Bye..

dream

answer is B

akshay.khare91

the Q . can be done by le chatlier principle
if we will increase the pressure then reaction will shift in the direction
where this increased pressure can be decreased .
since pressure is proportional to moles hence reaction will shift in direction where no of moles are less.

in a c d the no. of moles are less in product side hence reaction will shift in forward direction hence yield of product will increase
in b
the no. of moles are equal on both side hence there will be no
effect of pressure hence in this case only the yield of product cannot be increased by increase in pressure.
so ans is B
hope u got it!!!!!!

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