IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry - Sir please explain me.Please solve untill answer comes-confusing answer

nknikhilesh1

Ethanol and methanol form a solution that is very nearly ideal.The vapour pressure of ethanol is 44.5 mm and that of methanol is 88.7 mm at 20⁰C.

(a) Calculate the mole fraction of methanol and ethanol in a solution obtained by mixing 60g of ethanol and 40 g of methanol.

(b)Calculate the partial pressure and the total vapour pressure of this solution and the mole fraction of ethanol in the vapour.

krishna.gopal

(a)60 g ethanol = 60/46 mole
40 g methanol = 40/30 mole
So mole fraction of ethanol (xe)=(60/46)/((60/46)+(40/30))
mole fraction of methanol (xm)=1-xe
(b) Pe = xe*Poe
Pm=xm*Pom
P total=Pe+Pm
mole fraction of ethanol=Pe/(Pe+Pm)

Ask & Discuss Questions with Community & Experts