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Physical Chemistry

Blazing goIITian

Joined:	9 Sep 2007
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6 Mar 2008 22:42:53 IST

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362

soid state please quick

None

silver has an atomic radius of 144pm and the density of silver is 10.6g/cm^-3..

to which type of cubic crystal silver belongs to???????

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RISHIPRATIM MAZUMDAR

Blazing goIITian

Joined: 16 Jul 2007

Posts: 493

6 Mar 2008 22:48:54 IST

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apply the formula....
density = (z*a)/(N*v)
z=no. of particles in unit cell
a=atomic mass fr silver
N= avogadro's no.
v=volume of unit cell=(radius)^3
d=density
calculate z....
z=1 primitive
z=2 bcc
z=4 fcc

mukul bansal

Blazing goIITian

Joined: 9 Sep 2007

Posts: 640

6 Mar 2008 22:54:11 IST

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thanks dear

mukul bansal

Blazing goIITian

Joined: 9 Sep 2007

Posts: 640

7 Mar 2008 19:45:30 IST

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wait i have a doubt?????

how to take the volume????????

why have u considered the given radius as the unit cell edge length???????

Akhil

Blazing goIITian

Joined: 17 Jan 2008

Posts: 1451

7 Mar 2008 21:53:06 IST

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volume here will be edge length cube...take it as p
apply density now
and then find relation between r and p
this gives type of cubic metallic crystal

RISHIPRATIM MAZUMDAR

Blazing goIITian

Joined: 16 Jul 2007

Posts: 493

7 Mar 2008 22:45:27 IST

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yeah...dat ws a lil bit stupid of me.....
i meant vol=edge length cube.....
xtremely sorry 4 dat.....

RISHIPRATIM MAZUMDAR

Blazing goIITian

Joined: 16 Jul 2007

Posts: 493

7 Mar 2008 22:48:13 IST

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dat way,u can calculate the edge length from the above equation....
thn if edge length = 2r primitive
= (root 2)r - fcc
= (root 3)r - bcc

where r is the radius of the atom of silver.

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