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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Solid State-Formula of Compound
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harsha_27 (1353)

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In a compound, the atoms 'A' are present at three fourth of the corners and the atoms 'B' are present only at the diagonally opposite edge centers.If the 'C' atoms are present at the vacant corners and edges.Find the formula of the compound?

Solve.Get Rates.

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Indian_Dragon (95)

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sorry my answer is coming A4 B12 C27  and not A3 B2 C3 .
 

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sti (77)

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edited
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mona840 (717)

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yaar Indian dragon
 
u've dun everythin correct !!!!
 
bt aftr u get A 3/4   B 1 C 9/4
 
it cums 2    A3B4C9     

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Indian_Dragon (95)

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oh yes , i did a silly mistake.
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avi_1214545 (974)

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A3B4C9 is correct

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harsha_27 (1353)

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No No No................

A6B8C11 must be the answer.

"Nenenthedhavano naake teleedu"

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tarinbansal (3903)

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I am also getting A3B4C9.

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K4FECN6 (102)

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No, the answer must be A3B2C11.
Indian_Dragon,it seems for B atoms you have considered only "opposite edge centeres" and not "diagonally opposite edge centres".

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Indian_Dragon (95)

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i still couldn't get "diagonally opposite". diagonally opposite TO WHAT? ALL THE EDGE CNTRES ARE DIAGONALLY OPP. TO AT LEAST ONE OF THEM.
Hav you solved it?? K4FeCN6
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MUDIT (614)

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EVEN I REALLY DID NOT GET WHAT DIAGONALLY OPPOSITE MEANS AND I THINK EVERY ONE IS DOING A MISTAKE
WHEN YOU GET A AS 6x1/8 I DO NOT THINK THAT YOU CAN SIMPLIFY AND WRITE IT AS 3/4 AS WE ARE TRYING TO FIND MOLECULAR FORMULA AND NOT EMPERICAL FORMULA AND HENCE IF THE ANS DOES COME TO eg. A8B16C4 THAT WILL BE THE ANS AND NOT A2B4C
PLEASE CORRECT ME IF I AM WRONG

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