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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2008 10:03:10 IST
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In a compound, the atoms 'A' are present at three fourth of the corners and the atoms 'B' are present only at the diagonally opposite edge centers.If the 'C' atoms are present at the vacant corners and edges.Find the formula of the compound?
Solve.Get Rates.
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"Nenenthedhavano naake teleedu"
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2008 10:24:10 IST
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sorry my answer is coming A4 B12 C27 and not A3 B2 C3 .
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2008 13:55:11 IST
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edited 
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2008 16:27:25 IST
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yaar Indian dragon u've dun everythin correct !!!! bt aftr u get A 3/4 B 1 C 9/4 it cums 2 A3B4C9
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2008 16:34:44 IST
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oh yes , i did a silly mistake.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2008 16:38:09 IST
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A3B4C9 is correct
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2008 17:42:16 IST
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No No No................
A6B8C11 must be the answer.
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"Nenenthedhavano naake teleedu"
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2008 20:38:27 IST
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I am also getting A3B4C9.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Feb 2008 18:34:37 IST
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No, the answer must be A3B2C11. Indian_Dragon,it seems for B atoms you have considered only "opposite edge centeres" and not "diagonally opposite edge centres".
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ANAND KRISHNAN |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Feb 2008 19:40:52 IST
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i still couldn't get "diagonally opposite". diagonally opposite TO WHAT? ALL THE EDGE CNTRES ARE DIAGONALLY OPP. TO AT LEAST ONE OF THEM. Hav you solved it?? K4FeCN6
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Feb 2008 21:51:53 IST
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EVEN I REALLY DID NOT GET WHAT DIAGONALLY OPPOSITE MEANS AND I THINK EVERY ONE IS DOING A MISTAKE WHEN YOU GET A AS 6x1/8 I DO NOT THINK THAT YOU CAN SIMPLIFY AND WRITE IT AS 3/4 AS WE ARE TRYING TO FIND MOLECULAR FORMULA AND NOT EMPERICAL FORMULA AND HENCE IF THE ANS DOES COME TO eg. A8B16C4 THAT WILL BE THE ANS AND NOT A2B4C PLEASE CORRECT ME IF I AM WRONG
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