An Fcc cubic cell contains eight X atoms at the corners of the cell and six Y atoms at the faces.What is the impirical formula of the solid?

But how.can u please explain.

hi rahul i will explain it to u...

since x atoms are at corners therefore they are shared by 8 unit cells.

and y are at face centres therefore they are shared by 2 unit cells.

therefore x contribute 1/8 of cell and y cotribute 1/2 of unit cell.

there are eight corners therefore no of atom of x is 1/8*8=1 and there are 6 faces ,no of atom of y is 1/2*6=3

therefore formula is XY₃.

rate me plz if u r satisfied.