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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Apr 2008 00:31:42 IST
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A crystal lattice comprising A and B has NaCl structure, with A on each of the corners , B lying on any one of the axis are removed..find the formula of the lattice.
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10 Apr 2008 00:42:02 IST
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A4B15
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10 Apr 2008 00:46:17 IST
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can u pls xplain wot is meant by axis in d q???
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"Many of the things you can count,dont count....
Many of the things you cant count,really do count...."-Albert Einstein
"The important thing in science is not so much to obtain new facts as to discover new ways of thinking about them"-William Bragg
"An inexplicable fact is infinitely preferable to an incomprehensible mystery"-F. Soddy
RISHIPRATIM MAZUMDAR
NIT DURGAPUR
1ST YEAR,ELECTRONICS AND COMMUNICATIONS
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10 Apr 2008 01:05:08 IST
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its gonna be A3B2
see.... total A and B atoms are gonna be 4 each...contributn of each axis 4/3...B left 4 - 4/3 = 8/3
so now the new formula is A12 B 8 ie A3B2....
i suppose u meant B to be removed...ITs not very clear in the ques so i just assumed it
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15 Apr 2008 19:19:40 IST
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AB2 i think
A=1/8 X 8
B=1/2 X 4 [2 are removed]
Am i right pls any one repy
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15 Apr 2008 19:24:34 IST
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well see the co ordination no in NaCl structure is 4:4
when u remove one atom say B, the co ordination no ratio becomes 4:3
so i think the answer is A4B3
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16 Apr 2008 16:35:58 IST
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No the correct answer is A3B4...because in rock salt the corner particles also occupy the face centre....
Its an IIT 2001 question..
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