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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 20:38:56 IST
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The molarity and molality of a solution are M and m respectively . if the molecular weight of the solute is M' calculate the density of the solution in terms of M ,m and M'.
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9 Apr 2008 20:52:39 IST
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Let d be the density
Use the equation
m=1000M/(1000d-MM')
U will get the answer
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10 Apr 2008 20:34:22 IST
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but from where this formula of molality came.please derive
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10 Apr 2008 21:32:06 IST
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let weight of the solvent be w gm and weight of the solution be Wgm
then weight of the solvent=(W-w)gm
density D=W/V (V=volume of the solution)
molality m=(w x1000)/(M'x(W-w))
this implies, (W-w)=(w x1000)/(M'xm)
=> W=w [(1000+M'm)/M'm]
now,
molarity M=(w x1000)/(M' x V)
=> V=(w x1000)/(MxM')
now
D=W/V
=> D=[{(1000+M'm)/M'm}/{1000/MM'}]
=> D=[(1000+M'm)xMM'] / [1000x M'm]
open the brackets and u'll get-
M/m + MM'/1000
= M[1/m + M'/1000].......this is ur answer
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