Physical Chemistry

sudhindra shenoy's Avatar
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1 Sep 2011 23:36:48 IST
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stoichiometry
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 A sample was analysed and supposed to contain 21% NaOH by weight.Later it was found that basic material is KOH rather than NaOH .Find the % of KOH in the sample?



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New kid on the Block

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4 Sep 2011 16:00:17 IST
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i am also dont know


New kid on the Block

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4 Sep 2011 19:35:14 IST
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mole of the NAOH=mole of the KOH

New kid on the Block

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4 Sep 2011 19:53:37 IST
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found it
Krishna Gopal Singh's Avatar

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29 Feb 2012 23:51:53 IST
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100 g of mater was supposed to contain 21 g NaOH. But 21 g NaOH is equivalent to 21*56/40 =
Krishna Gopal Singh's Avatar

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29 Feb 2012 23:53:16 IST
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 Sorry for incomplete answer.

So 21 g NaOH = 21*56/40 = 29.4 g. So mixture contains 29.4 g KOH by weight.




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