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Physical Chemistry
Stoichiometry
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pls help me out with these 4 questions.
1. A natural gas sample contains 84%(by volume) of CH4, 10% of C2H6, 3% of C3H8 & 3% of N2. if a series of catalytic reactions cud be used for converting all the C atoms of the gas into butadiene, C4H6, with 100% efficiency, how much butadiene cud be prepared from 100 g of the natural gas?
2. What weights of P4O6 & P4O10 will be produced by the combustion of 2g of P4 in 2g of O2 leaving no P4 & O2?
3. From the following reactions calculate how much F2 will be consumed to produce 1kg of (CF2)n.
2CoF2 + F2 -> 2CoF3
(CH2)n + 4nCoF3 -> (CF2)n + 2nHF + 4nCoF2
4. 1 litre of an acidified sol of KMnO4 containing 15.8g of KMnO4 is decolourised by passing sufficient amt of SO2. if SO2 is produced by roasting of FeS2, what will be the amt of FeS2 required to produce the necessary amt of SO2?
pls answer these using POAC. thanx in advance cos i hv to go now.
Comments (7)
BALGANESH
Blazing goIITian

Joined: 14 Nov 2007
Posts: 309
20 Mar 2008 10:10:20 IST
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3)
50.n g of CF2 requires = 115 .4n g of CoF3 requires
therefore 1000g 0f CF2 requires =9200g of CoF3
NOW 2. 115 g of Cof3 requires 38 of F2
therefroe 9200g of CoF3 requires 38.9200/2. 115 =1520g
note molecular weigt of Cof3 = 115g and THAT of F2 = 38g
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20 Mar 2008 11:26:50 IST
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1)
volume
moles ( weight of the given compound)
moles ( weight of the given compound)therefore 84 % of CH4 = 84 of CH4
now consider the reaction
4CH4 - 5H2 = C2H6
here 4.16 g of CH4 gives 54 g of C2H6
threfore 84 g of CH4 = 70.875
similarly for the other compound
10 g OF C2H6 = 9 g of C2H6
3 gof C3H8 = 2.76 g OF C2H6
adding these we egt the total mass of the required copmpound =82.635 g
21 Mar 2008 01:32:50 IST
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according to the reaction
2KMnO4 + H2SO4 +5SO2 = K2SO4 + MnSO4 + 5S03
(BALANCE ONLY THE REQUIRED PART)
2 . 158 g of KMnO4 = 320 g og S02
therefore 15.8 g of KMnO4 = 16 g of S02
now see the reaction
4Fes2 + 5o2 = 8SO2 + 2FeO3
from the reaction
512 g of SO2 = 480 g of FeS2
therefore 16 g of SO2 = 15 g of FeS2
rate if correct or useful











