IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

m.mangalam

1) What reaction will take place between acidic medium of KMnO₄ + FeC₂O₄

2)What does mean by solution of x volume e.g. 10 volume

3)Sample of oleum is labelled 109%.The % of free SO₃in the sample is equal to ?( oleum is SO₃ + H₂SO₄)

DON007

i m not understanding ur 2nd question..............

but in 1st reaction..................as KMnO4 is an oxidizing agent................therefore it will convert Fe2+ TO Fe 3+...........................and C₂O₄^2-_{^{to CO2 .........................therefore...............}}

_{^{and in acidic medium...........................}}

_{^{MnO4 - to Mn 2+..............................}}

_{^{and in 3rd question is the answer 40%...........................i m not sure.................}}

_{^{thanku....................i know there r many terms missing.................as time is very less.....................i have to save my time.......................}}

_^thanku

taruntanuj007

KMnO4 + FeC2O4 gives Mn2+ + Fe3+ + 2CO2

n factor for KmnO4 = 5

ferrous oxallate = 3

x volume refers to the volume of oxygen evolved when the amount of hdrogen peroxide is put in water read up some book i dont remember the exact values

remember molarity of h2O2 = X/11.2 normality = X/5.6 where X is the volume

109 % oleum refers to the volume of acid formed when the oleum is dissolved in 1litre water now calculate do rate me!!!!

Moderator

Experts only answer one question at a time, please let us know which of these you want to be answered first and post other questions on a new page.

~ moderator

m.mangalam

plz give the answer for my third question first

khyatigupta

3) u must be knwing tht 109% of H2SO4 refers to the total mass of H2SO4 ie 109g will be formed when 100g of oleum is diluted by 9 g of H2O which combines with free SO3 present in oleum to form H2SO4

nw acc to this rxn,

H2O+ SO3------H2SO4

here 1 mole of H2SO4 combines with 1 mole of SO3.

or 18 g of H2O combine with 80g of SO3

tht means 9g of it will combine with 40g of SO3

thus, u cn say tht 100g of oleum contains 40g of SO3 .

Hence oleum contains 40% of free SO3.

tht's the solution.....

smriti.mathur

Mol.wt of oleum H₂ S₂ O₇ is 178

In this, SO₃ is 80gm.

Therefore, in 109gm oleum, SO₃ is

80/178 * 109 = 49

= 49%

Ask & Discuss Questions with Community & Experts