A 360 g sample of 80% Nahco₃ and 60% Naco₃ is subjeted to thermal decomposition in a container fitted with a condenser. The loss in weight was found to be 66g. Find out the composition of sodium bicarbonate and sodium carbonate in the mixture....

give a answer with detailed solution. the answer is 315 gms of Nahco₃ n 45 gms of Naco_{3 .}RATES FOR SURE........

PLEASE ANSWER THIS.............PLEASE........ TELL ME IF U DON'T KNOW////////////

it's a pity that i have to find the answer from different site n post it here for everyone's benefit. i do not wat hapenned for goiit. I EARLIER POSTED THE SAME QUESTION, but didn't get the correct answer so i asked  it as a expert question here, but no ans here too...........

so iam answering my own question now..........

2NaHco₃ ------------- >  Naco₃ + co₂+ H₂O

168 gms ------------> 44 co₂   ( for loss in weight, CO₂ gas must be taken into account)

x gms -------------> 66 gms of co₂

x = 252 gms of NaHco₃  by solving

=> 252 x 100/80 (as the mixture contains  80% of NaHco₃ ) = 315 gms....

=>  360 - 315 = 45 gm of  Naco₃

please correct if it wrong.......

The answer posted appears to be correct. As I am not good in solving such problems I had to verify the mathematical calculations from some enjineering student. As the answer matches with the given answer we may consider it to be correct.

However, I have my own doubt as the temp. of thermal decomposition is not mentioned the final product should be the oxide ( observation of our research work on thermal decomposition of some inorganic compounds). In such case the calculations will change, and you can then modify them .